HP T100 Instructions d'exploitation télécharger pdf (Page 11)

01 2 0 0 7 4 0 0 2 = ? 1 0 8C

48 49 50 48 48 55 52 48 48 50 61 63 49 48 56 13

a1 a2 a3 1 0 p1 p2 p3 I1 I2

c1 c2 c3 C

The following possible telegrams are transferred with 9600 baud, 8 data bits, no parity and 1

stop bit.

Write request to transmitter

data

a1 a2 a3 1 0 p1 p2 p3 I1 I2

c1 c2 c3 C

Answer of transmitter

a1, a2, a3: Unit address (“001” ... “015”, also see chapter 3.3 )

p1, p2, p3: number (see table)

I1, I2: data length (see table)

data: see table or “NO_DEF”: wrong parameter number, “_LOGIC”: Access fault,

“_RANGE”: Out of range

c1, c2, c3: checksum, sum of all ASCII up to checksum modulo (remainder) 256,

for example “0120074002=?” => 48+49+50+ ... +61+63=620,

620 modulo 256 = 108 => “108”

: Carriage return (ASCII code 13)

data

a1 a2 a3 0 0 p1 p2 p3 0 2 = ? c1 c2 c3 C

Read request to transmitter

For example the character string and the ASCII code corresponds as follows:

4.2. Communication

The transmitter communicates via the serial interface with the respective display units (plea-

se see "Accessories"), but alternatively can also be controlled directly via the RS 232 or

RS 485 by means of the interface protocol.

The Interface protocol is in ASCII format which means that all data bytes are representable

symbols with an ASCII code ≥ 32 with the exception of the telegram final symbol carriage

return (

, 13).

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HP T100 Instructions d'exploitation Page 11